

단순한 사칙연산으로 다음을 구한다.
$$ A \times12 +B $$
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
using vi = vector<int>;
using vll = vector<ll>;
using vpii = vector<pii>;
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define F first
#define S second
#define pb push_back
#define mp make_pair
#define lb lower_bound
#define ub upper_bound
#ifndef ONLINE_JUDGE
template<typename A, typename B>
ostream& operator<<(ostream& os, const pair<A, B>& p) {
return os << "{" << p.first << ", " << p.second << "}";
}
template<typename T>
ostream& operator<<(ostream& os, const vector<T>& v) {
os << "[";
for (size_t i = 0; i < v.size(); ++i) {
os << v[i];
if (i != v.size() - 1) os << ", ";
}
return os << "]";
}
#define debug(...) cerr << "[DEBUG] " << #__VA_ARGS__ << ": ", DBG(__VA_ARGS__)
template<typename T> void DBG(const T& v) { cerr << v << endl; }
template<typename T, typename... Args> void DBG(const T& v, const Args&... args) { cerr << v << ", "; DBG(args...); }
#else
#define debug(...)
#endif
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int A, B;
cin >> A >> B;
cout << A * 12 + B << "\\n";
return 0;
}